x^2-160x+5860=0

Solution for x^2-160x+5860=0 equation:

x^2-160x+5860=0

a = 1; b = -160; c = +5860;
Δ = b2-4ac
Δ = -1602-4·1·5860
Δ = 2160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2160}=\sqrt{144*15}=\sqrt{144}*\sqrt{15}=12\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-12\sqrt{15}}{2*1}=\frac{160-12\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+12\sqrt{15}}{2*1}=\frac{160+12\sqrt{15}}{2}
$